12y^2+19y+5=0

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Solution for 12y^2+19y+5=0 equation:


Simplifying
12y2 + 19y + 5 = 0

Reorder the terms:
5 + 19y + 12y2 = 0

Solving
5 + 19y + 12y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(5 + 4y)(1 + 3y) = 0

Subproblem 1

Set the factor '(5 + 4y)' equal to zero and attempt to solve: Simplifying 5 + 4y = 0 Solving 5 + 4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + 4y = 0 + -5 Combine like terms: 5 + -5 = 0 0 + 4y = 0 + -5 4y = 0 + -5 Combine like terms: 0 + -5 = -5 4y = -5 Divide each side by '4'. y = -1.25 Simplifying y = -1.25

Subproblem 2

Set the factor '(1 + 3y)' equal to zero and attempt to solve: Simplifying 1 + 3y = 0 Solving 1 + 3y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 3y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 3y = 0 + -1 3y = 0 + -1 Combine like terms: 0 + -1 = -1 3y = -1 Divide each side by '3'. y = -0.3333333333 Simplifying y = -0.3333333333

Solution

y = {-1.25, -0.3333333333}

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